A 2.80 kg block starts from rest at the top of a 30.0\textdegree incline and slides a distance of 2.30 m down the incline in 1.80 s. (a) Find the magnitude of the acceleration of the block. 1.42 m/s$^2$ (b) Find the coefficient of kinetic friction between block and plane. 0.577 $\tan(\theta_{max})$ is the equation for the static coefficient of friction when the surface is inclined at the angle that just starts the object sliding. That is not the problem described here. (c) Find the friction force acting on the block. 13.7 magnitude Draw a careful free-body diagram of the forces acting on the block. Determine the components of the vectors in a coordinate system parallel and perpendicular to the incline. N direction up the incline (d) Find the speed of the block after it has slid 2.30 m. 2.6 m/s
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We can use the equation for acceleration on an inclined plane: a = g * sin(theta) where g is the acceleration due to gravity (9.8 m/s^2) and theta is the angle of the incline (30 degrees). a = 9.8 m/s^2 * sin(30 degrees) a = 9.8 m/s^2 * 0.5 a = 4.9 m/s^2 So Show more…
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