Question

A7.1 Sketch the polar plot for the following loop transfer functions: Solutions must be done by hand on graph paper. (a) $G_c(s)G(s) = \frac{1}{(1 + 0.5s)(1 + 2s)}$ (b) $G_c(s)G(s) = \frac{10(s^2 + 1.4s + 1)}{(s - 1)^2}$ (c) $G_c(s)G(s) = \frac{s - 10}{s^2 + 6s + 10}$ (d) $G_c(s)G(s) = \frac{30(s + 8)}{s(s + 2)(s + 4)}$

          A7.1 Sketch the polar plot for the following loop transfer functions:
Solutions must be done by hand on graph paper.
(a) $G_c(s)G(s) = \frac{1}{(1 + 0.5s)(1 + 2s)}$
(b) $G_c(s)G(s) = \frac{10(s^2 + 1.4s + 1)}{(s - 1)^2}$
(c) $G_c(s)G(s) = \frac{s - 10}{s^2 + 6s + 10}$
(d) $G_c(s)G(s) = \frac{30(s + 8)}{s(s + 2)(s + 4)}$

A7.1 Sketch the polar plot for the following loop transfer functions:
Solutions must be done by hand on graph paper.
(a) Gc(s)G(s) = (1)/((1 + 0.5s)(1 + 2s))
(b) Gc(s)G(s) = (10(s^2 + 1.4s + 1))/((s - 1)^2)
(c) Gc(s)G(s) = (s - 10)/(s^2 + 6s + 10)
(d) Gc(s)G(s) = (30(s + 8))/(s(s + 2)(s + 4))

Added by Paul T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Babita Kumari

Step 1

For the first transfer function, we have G(s) = 10/(s^2 + 6s + 10). To sketch the polar plot, we need to find the magnitude and phase of G(s) for different values of frequency (ω). First, let's find the magnitude |G(s)|: |G(s)| = 10/|s^2 + 6s + 10| Next, let's Show more…

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A7.1 Sketch the polar plot for the following loop transfer functions: Solutions must be done by hand on graph paper. 1 s=15=10 (cGs)G(s= s^2 +6s+10 30(s + 8 dGsGs= s(s + 2)(s + 4)