A 73 kg bike racer climbs a 1300-m-long section of road that has a slope of 4.3 ° . By how much does his gravitational potential energy change during this climb? Express your answer with the appropriate units. ?U =
Added by Zachary F.
Close
Step 1
Given: Length of the road (L) = 1300 m, Slope (sin(theta)) = 4.3% Height (h) = L * sin(theta) Height (h) = 1300 * 0.043 Height (h) = 56.9 m Show more…
Show all steps
Your feedback will help us improve your experience
Mahajan A and 86 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Madhur L.
A 70 kg bicyclist is coasting down a long hill with a 3.5° slope. He's moving quite rapidly, so air drag is important. His cross-sectional area is 0.32 m^2 and his drag coefficient is 0.88. What speed does he eventually reach, in mph?
The power output of professional cyclists averages about $350 \mathrm{~W}$ when climbing mountains. How much energy does a typical 70 -kg pro cyclist expend climbing a 12.3-km-long mountain road with a $3.9^{\circ}$ average slope at an average speed of $22.5 \mathrm{~km} / \mathrm{h}$ ? Example $6-14$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD