A 82 g Frisbee is thrown from a point 1.4 m above the ground with a speed of 16 m/s. When it has reached a height of 2.1 m, its speed is 14 m/s. What was the reduction in the mechanical energy of the Frisbee-Earth system because of air drag?
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The initial mechanical energy of the Frisbee-Earth system can be calculated using the formula: E_initial = KE_initial + PE_initial where KE_initial is the initial kinetic energy and PE_initial is the initial potential energy. Given: KE_initial = 1/2 * m * Show more…
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. Frisbee A $75 \mathrm{~g}$ Frisbee is thrown from a point $1.1 \mathrm{~m}$ above the ground with a speed of $12 \mathrm{~m} / \mathrm{s}$. When it has reached a height of $2.1 \mathrm{~m}$, its speed is $10.5 \mathrm{~m} / \mathrm{s}$. What was the reduction in the mechanical energy of the Frisbee-Earth system because of air drag?
A 75 g Frisbee is thrown from a point 1.1 $\mathrm{m}$ above the ground with a speed of 12 $\mathrm{m} / \mathrm{s}$ . When it has reached a height of $2.1 \mathrm{m},$ its speed is 10.5 $\mathrm{m} / \mathrm{s}$ . What was the reduction in $E_{\mathrm{mec}}$ of the Frisbee-Earth system because of air drag?
A 75 g Frisbee is thrown from a point 1.1 m above the ground with a speed of 12 m/s. When it has reached a height of 2.1 m, its speed is 10.5 m/s. What was the reduction in mechanical energy of the Frisbee-Earth system because of air drag?
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