00:01
So in this question, we are given three cylinders, each with the same volume of gas in them, and the gases are all at the same temperature, but they differ in the piston that is containing the gas and where that piston is located.
00:21
So in order to answer the question about the pressure in the gases, let us consider the forces that act on each piston, and we'll draw a free body diagram for each of those.
00:34
Now, in the first one, there is the piston is located on top of the gas, and we have the force of gravity acting on that piston.
00:44
Let's call it little m times g.
00:47
We also have going down over here, we have the air pressure from the outside air, which is p .0 times a.
00:57
That's the force caused by that air pressure.
00:59
And then going up, we are going to have the force exerted by the inside air pressure.
01:07
We'll call that p1 times a.
01:14
And so the equation would be p1a is equal to p0a plus mg, since the upward forces need to balance the downward pointing forces.
01:38
Now, the second piston is going to be very similar, but the only difference here is that the size of the piston is different.
01:47
It's got a different mass, got more mass.
01:50
And so therefore, p2a is going to equal to p0 times a.
01:57
Again, it's a cross -sectional area of my piston, which is still the same.
02:03
Plus, let's just call it uppercase m because it's the bigger mass times g...