To predict the sign of \( \Delta S^{\circ} \), we need to consider the change in the number of moles of gas during the reaction. The reaction starts with \( \frac{13}{2} \) moles of \( \mathrm{O}_{2} \) gas and 1 mole of \( \mathrm{C}_{4}\mathrm{H}_{10} \) gas,
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