5- A = \begin{bmatrix} a_{ij} \end{bmatrix}_{3x3} = \begin{bmatrix} \frac{1}{i+j-1} \end{bmatrix}_{3x3} olmak üzere iz(A) =? a) \text{ } -15/23 b) \text{ } 0 c) \text{ } 15/23 d) \text{ } 23/15 e) \text{ } -23/15 Leave blank
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The matrix A is a 3x3 matrix, so we will fill in the elements accordingly. A = [a_(ij)]_(3x3) = [1/(i+j-1)]_(3x3) A = | 1/(1+1-1) 1/(1+2-1) 1/(1+3-1) | | 1/(2+1-1) 1/(2+2-1) 1/(2+3-1) | | 1/(3+1-1) 1/(3+2-1) 1/(3+3-1) | Show more…
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