About 8 women in 100,000 have cervical cancer $(\mathrm{C})$, so $\mathrm{P}(\mathrm{C})=0.00008$ and $\mathrm{P}(\mathrm{noC})=0.99992 .$ The chance
that a Pap smear will incorrectly indicate that a woman without cervical cancer has cervical cancer is $0.03$. Therefore.
$$
P(\text { test } p o s \mid n o C)=0.03
$$
What is the probability that a randomly chosen women who has this test will both be free of cervical cancer and test positive for cervical cancer (a false positive)?