00:01
So in this question, we are comparing here, we want to perform a task in which the variance, the population, is assumed to be equal to the value 1 .3 or if we can say that it is actually different than the value.
00:16
So in this case, because we are working with variances, the task that we're going to perform is based on the k -square distribution.
00:25
And the task statistic here is given us the number of observations that we have minus 1, the sample variance, over the variance assumed to be the value in the population.
00:41
So the number of observations that we have is 8, so 8 minus 1.
00:46
The standard deviation is 1 .8, and so the sample variance is just a value square.
00:53
And we are assuming that the value in the population is 1 .3 for the variance.
00:58
So if you compute this, you're going to get 17 .446.
01:03
And now we can either compare this to the critical value, find the p value...