Question

According to a 2010 report from the American Council on Education, females make up 57% of the college population in the United States. Students in a statistics class at South Texas College want to determine the proportion of female students at STC. They select a random sample of 135 STC students and find that 72 are female, which is a sample proportion of 72 / 135 ? 0.533. So 53.3% of the students in the sample are female. That is, the sample proportion, p? = 0.533 What can they conclude about the proportion of females at the college? How confident can they be in their estimate? To answer these questions, we need to find a confidence interval to estimate the population proportion. Margin of Error, E = Z?/2?(pq/n) and for the confidence interval use p? ± Margin of Error You Task: 1. Find the Margin of Error 2. Find confidence interval 3. Conclusion: We are 95% confident that the proportion of all STC students who are female is between ------- and --------

          According to a 2010 report from the American Council on Education, females make up 57% of the college population in the United States. Students in a statistics class at South Texas College want to determine the proportion of female students at STC. They select a random sample of 135 STC students and find that 72 are female, which is a sample proportion of 72 / 135 ? 0.533. So 53.3% of the students in the sample are female. That is, the sample proportion, p?

= 0.533

What can they conclude about the proportion of females at the college? How confident can they be in their estimate?

To answer these questions, we need to find a confidence interval to estimate the population proportion.

Margin of Error, E = Z?/2?(pq/n)

and for the confidence interval use p? ± Margin of Error

You Task:

1. Find the Margin of Error

2. Find confidence interval

3. Conclusion:

We are 95% confident that the proportion of all STC students who are female is between ------- and --------

According to a 2010 report from the American Council on Education, females make up 57% of the college population in the United States. Students in a statistics class at South Texas College want to determine the proportion of female students at STC. They select a random sample of 135 STC students and find that 72 are female, which is a sample proportion of 72 / 135 ? 0.533. So 53.3% of the students in the sample are female. That is, the sample proportion, p?

= 0.533

What can they conclude about the proportion of females at the college? How confident can they be in their estimate?

To answer these questions, we need to find a confidence interval to estimate the population proportion.

Margin of Error, E = Z?/2?(pq/n)

and for the confidence interval use p? ± Margin of Error

You Task:

1. Find the Margin of Error

2. Find confidence interval

3. Conclusion:

We are 95% confident that the proportion of all STC students who are female is between ------- and --------

Added by Juan Francisco C.

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