According to a Bureau of Labor Statistics, a worker in the U.S. spends on average 528 minutes a day on the job. Suppose the standard deviation of the time spent on the job is 36 minutes. What is the probability that a sample of 81 workers have a mean time more than 533 minutes?
Added by David B.
Step 1
Step 1: Calculate the standard error of the mean (sigma X bar): Given standard deviation (sigma) = 36 minutes Number of samples (n) = 81 Standard error (sigma X bar) = sigma / sqrt(n) sigma X bar = 36 / sqrt(81) sigma X bar = 36 / 9 sigma X bar = 4 Show more…
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