According to a poll, 625 out of 1058 randomly selected smokers polled believed they are discriminated against in public life or in employment because of their smoking. a. What percentage of the smokers polled believed they are discriminated against because of their smoking? b. Check the conditions to determine whether the CLT can be used to find a confidence interval c. Find a 95% confidence interval for the population proportion of smokers who believe they are discriminated against because of their smoking. d. Can this confidence interval be used to conclude that the majority of smokers believe they are discriminated against because of their smoking? Why or why not?
Added by Andrew H.
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The percentage of the smokers polled who believed they are discriminated against because of their smoking can be calculated by dividing the number of smokers who believed they are discriminated against by the total number of smokers polled and then multiplying by Show more…
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According to a 2017 Gallup poll, 572 out of 1021 randomly selected smokers polled believed they are discriminated against in public life or in employment because of their smoking. a. What percentage of the smokers polled believed they are discriminated against because of their smoking? b. Check the conditions to determine whether the CLT can be used to find a confidence interval. c. Find a $95 \%$ confidence interval for the population proportion of smokers who believe they are discriminated against because of their smoking. d. Can this confidence interval be used to conclude the majority of Americans believe smokers are discriminated against because of their smoking? Why or why not?
According to a poll, 676 out of 1025 randomly selected smokers polled believed they are discriminated against in public life or in employment because of their smoking. a. What percentage of the smokers polled believed they are discriminated against because of their smoking? b. Check the conditions to determine whether the CLT can be used to find a confidence interval. c. Find a 95% confidence interval for the population proportion of smokers who believe they are discriminated against because of their smoking. d. Can this confidence interval be used to conclude that the majority of smokers believe they are discriminated against because of their smoking? Why or why not? a. The percentage of those taking the poll believed they are discriminated against because of their smoking is %. (Round to one decimal place as needed.) b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. The Random and Independent condition can reasonably be assumed to hold. The Large Sample condition holds. The Big Population condition holds. c. The 95% confidence interval is ( , ). (Round to three decimal places as needed.) d. Can this confidence interval be used to conclude that the majority of smokers believe they are discriminated against because of their smoking? Why or why not? Yes, because the confidence interval includes values above and below 50%.
Sri K.
(a) identify the claim and state $H_{0}$ and $H_{a}$ (b) find the standardized test statistic z. If convenient, use technology. (c) find the P-value. If convenient, use technology. (d) decide whether to reject or fail to reject the null hypothesis. (e) interpret the decision in the context of the original claim. The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 6.2 years. At $\alpha=0.05,$ is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years? (Adapted from The Gallup Poll) $$\begin{array}{ccccccccccc}15.7 & 13.2 & 22.6 & 13.0 & 10.7 & 18.1 & 14.7 & 7.0 & 17.3 & 7.5 & 21.8 \\12.3 & 19.8 & 13.8 & 16.0 & 15.5 & 13.1 & 20.7 & 15.5 & 9.8 & 11.9 & 16.9 \\7.0 & 19.3 & 13.2 & 14.6 & 20.9 & 15.4 & 13.3 & 11.6 & 10.9 & 21.6 &\end{array}$$
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