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Good day, the topic is about binomial distribution.
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In a binomial distribution, the probability is either a success or a failure.
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In this type of distribution, the number of observations or trials is fixed, and that each observation or trial is independent from each other.
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And also, the probability of success is exactly the same from one trial to another.
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In this problem, we are given that in a survey of 25 ,000 households, 57 % or that's 0 .57 says that they watch special event on tv after commercials.
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In this problem we wish to find if a random sample of 9 people are surveyed, what is the probability that exactly 3 would enjoy the commercials more than the event and that less than 4 would enjoy commercials more than the event? it's part b.
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For part c we want to find exactly 5 or 6 people would enjoy commercials more to the event and finally we wish to find the mean and the standard deviation for the distribution since this distribution only has two outcomes either either liking the commercial which probability is 57 % and not liking the commercial which is probability is 43 % so this one is a binomial probability distribution so to start let's have for the first one, we have the probability three, three fall out of nine would like the commercial modern event...