00:02
Hello students, let us do this question.
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Here, p is the proportion of casual dining restaurant that earn a profit of less than $50 ,000 last year.
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For this we have given sample of size n is equal to 142 and in which x is the number of casual dining restaurant that earn profit of less than $50 ,000 last year, which is obtained as 81.
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The point estimate for the population proportion is sample proportion.
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Sample proportion denoted as t hat.
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It is computed as x divided by n.
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From the given information it is 81 divided by 142 which is equal to 0 .5704.
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So the point estimate for the population proportion is 0 .5704.
01:07
Part b, in order to estimate 95 % confidence interval for population proportion p, we first need to compute the margin of error.
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Margin of error is given as z -alpha by 2 p -hat into 1 minus p -hat divided by n in this square root...