According to the following reaction, how many milliliters, mL of
0.309 M HCl is needed to neutralize 10.20 grams of
Ca(OH)2? Just give the numerical value. The assumption
is the answer is in milliliters, mL.
Reaction:
2 HCl(aq) + Ca(OH)2(aq) --> 2
H2O(l) + CaCl2(aq)