00:02
In this problem, we're looking at i -03 minus, and we want our best fluid structure.
00:08
So let's start by looking at the number of valance electrons.
00:12
So iodine has 7, each oxygen has 6, and our minus charge here tells us that we add an extra 1.
00:22
So we get a total of 26 electrons.
00:27
And if we consider every outer atom, so every oxygen gets an octet.
00:31
That's 24 electrons.
00:35
So because we have a two electron difference here, that means we have two electrons on our central atom, and we know we at least have one bond to each oxygen, but now we need to use what we know about different groups to help us here.
00:54
So if we have our halogen in the middle, ideally we want one electron pair plus six bonds, and that would give us a neutral iodine.
01:12
If we want neutral oxygens, we want two electron pairs and two bonds.
01:21
So right now we have three bonds...