00:01
Here in this problem, given a solution of noh has a ph of 9 .52.
00:12
And we have to calculate the poh, concentration of hydonia ions, and concentration of oh minus ions.
00:22
Now here the ph given 9 .52 at 25 degrees celsius.
00:27
First we will calculate concentration of hydonia ions.
00:31
What is ph? that is negative log concentration of hydroneyam ions and that is equal to 9 .52.
00:39
So you can write log of concentration of hydonia ions is negative 9 .52.
00:47
So concentration of hydunium ions that will be 10 to the power of negative 9 .52 and that is 3 .02 times 10 to the power of negative 10 molar.
01:02
The concentration of hydronium ions.
01:05
Now, we have to calculate p .o .h and o .h minus ion concentration.
01:11
Now, we know for a solution, ph plus pohh is equal to 14...