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Acids and Bases Calculating the pH at equivalence of a titration ( 2 / 5 ) A chemist titrates ( 60.0 mathrm{~mL} ) of a ( 0.5545 M ) cyanic acid ( (mathrm{HCNO}) ) solution with ( 0.6437 M mathrm{KOH} ) solution at ( 25{ }^{circ} mathrm{C} ). Calculate the pH at equivalence. The ( p K_{a} ) of cyanic acid is 3.46 . Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of ( mathrm{KOH} ) solution added. [ mathrm{pH}= ] ( square )

          Acids and Bases
Calculating the pH at equivalence of a titration
( 2 / 5 )
A chemist titrates ( 60.0 mathrm{~mL} ) of a ( 0.5545 M ) cyanic acid ( (mathrm{HCNO}) ) solution with ( 0.6437 M mathrm{KOH} ) solution at ( 25{ }^{circ} mathrm{C} ). Calculate the pH at equivalence. The ( p K_{a} ) of cyanic acid is 3.46 .

Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of ( mathrm{KOH} ) solution added.
[
mathrm{pH}=
]
( square )

Acids and Bases
Calculating the pH at equivalence of a titration
( 2 / 5 )
A chemist titrates ( 60.0 mathrm mL ) of a ( 0.5545 M ) cyanic acid ( (mathrmHCNO) ) solution with ( 0.6437 M mathrmKOH ) solution at ( 25 ^circ mathrmC ). Calculate the pH at equivalence. The ( p Ka ) of cyanic acid is 3.46 .

Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of ( mathrmKOH ) solution added.
[
mathrmpH=
]
( square )

Added by Shania E.

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