Question

Line segment NY has endpoints N(-11,5) and Y(5, -7). What is the equation of the perpendicular bisector of NY? y + 1 = 4(x + 3) y + 1 = 3(x + 3) y - 6 = -3(x - 8)

Name: acpo line segment ny has endpoints n 115 and y5 7 what is the equation of the perpendicular bisector of ny y1 4 x3 3 y1 3 x 3 y 6 f 8 y 6 3 x 8 submit answer 62438
Uploaded: 2023-01-13T12:42:30-08:00
Duration: 1 min 41 s
Channel: Donna Densmore
Description: acpo line segment ny has endpoints n 115 and y5 7 what is the equation of the perpendicular bisector of ny y1 4 x3 3 y1 3 x 3 y 6 f 8 y 6 3 x 8 submit answer 62438

          Line segment NY has endpoints N(-11,5) and Y(5, -7). What is the equation of the perpendicular bisector of NY?
y + 1 = 4(x + 3)
y + 1 = 3(x + 3)
y - 6 = -3(x - 8)

Added by Mary A.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Donna Densmore

01/13/2023

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y+1 = 4 (x+3) 3 y+1 = 3 (x + 3) Show more…

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Line segment NY has endpoints N(-11,5) and Y(5, -7). What is the equation of the perpendicular bisector of NY? y + 1 = 4(x + 3) y + 1 = 3(x + 3) y - 6 = -3(x - 8)