We can use the z-score formula to standardize the score:
$z = \frac{x - \mu}{\sigma}$
where $x$ is the score, $\mu$ is the mean, and $\sigma$ is the standard deviation. Plugging in the values, we get:
$z = \frac{23 - 21.1}{5.1} \approx 0.373$
Now, we want to
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