Question

Activity 2: \#FightCOVID19 Directions: Solve each of the following and write the matching letter on the blank above the answer to decode the message to get us through the Corona Virus shutdown. (Show complete solution.) 0 \( -2 \sqrt{20}+2 \sqrt{18}-2 \sqrt{5} \) H \( -4 \sqrt{5}(4-3 \sqrt{10}) \) 1. \( \frac{\sqrt{2}+\sqrt{8}}{6 \sqrt{24}} \) N \( -3 \sqrt{27 x}-3 \sqrt{3 x} \) S \( (-2 \sqrt{3}+2)(\sqrt{3}-5) \) E \( \sqrt{27 x^{2} y}+x \sqrt{12 y} \) A \( \frac{3 \sqrt{6 x}-\sqrt{4}}{2 \sqrt{3}} \) W \( 2 \sqrt{x y}+2 \sqrt{y}+9 \sqrt{x y} \) \[ 11 \sqrt{x y}+2 \sqrt{y} \leq 5 x \sqrt{3 y} \quad-16 \sqrt{5}+60 \sqrt{2} 5 x \sqrt{3 y} \frac{9 \sqrt{2 x}-2 \sqrt{3}}{6} \quad \frac{\sqrt{3}}{12} \quad \frac{9 \sqrt{2 x}-2 \sqrt{3}}{6}-16+12 \sqrt{1} \quad-6 \sqrt{5}+6 \sqrt{2}-12 \sqrt{1 x} \quad 5 x \sqrt{7 y} \]

          Activity 2: \#FightCOVID19
Directions: Solve each of the following and write the matching letter on the blank above the answer to decode the message to get us through the Corona Virus shutdown.
(Show complete solution.)
0 \( -2 \sqrt{20}+2 \sqrt{18}-2 \sqrt{5} \)
H \( -4 \sqrt{5}(4-3 \sqrt{10}) \)
1. \( \frac{\sqrt{2}+\sqrt{8}}{6 \sqrt{24}} \)

N \( -3 \sqrt{27 x}-3 \sqrt{3 x} \)
S \( (-2 \sqrt{3}+2)(\sqrt{3}-5) \)
E \( \sqrt{27 x^{2} y}+x \sqrt{12 y} \)
A \( \frac{3 \sqrt{6 x}-\sqrt{4}}{2 \sqrt{3}} \)
W \( 2 \sqrt{x y}+2 \sqrt{y}+9 \sqrt{x y} \)
\[
11 \sqrt{x y}+2 \sqrt{y} \leq 5 x \sqrt{3 y} \quad-16 \sqrt{5}+60 \sqrt{2} 5 x \sqrt{3 y} \frac{9 \sqrt{2 x}-2 \sqrt{3}}{6} \quad \frac{\sqrt{3}}{12} \quad \frac{9 \sqrt{2 x}-2 \sqrt{3}}{6}-16+12 \sqrt{1} \quad-6 \sqrt{5}+6 \sqrt{2}-12 \sqrt{1 x} \quad 5 x \sqrt{7 y}
\]

Activity 2: #FightCOVID19
Directions: Solve each of the following and write the matching letter on the blank above the answer to decode the message to get us through the Corona Virus shutdown.
(Show complete solution.)
0 -2 √(20)+2 √(18)-2 √(5)
H -4 √(5)(4-3 √(10))
1. (√(2)+√(8))/(6 √(24))

N -3 √(27 x)-3 √(3 x)
S (-2 √(3)+2)(√(3)-5)
E √(27 x^2 y)+x √(12 y)
A (3 √(6 x)-√(4))/(2 √(3))
W 2 √(x y)+2 √(y)+9 √(x y)

11 √(x y)+2 √(y)≤ 5 x √(3 y) -16 √(5)+60 √(2) 5 x √(3 y)(9 √(2 x)-2 √(3))/(6) (√(3))/(12) (9 √(2 x)-2 √(3))/(6)-16+12 √(1) -6 √(5)+6 √(2)-12 √(1 x) 5 x √(7 y)

Added by Zachary O.

Question

Please give Ace some feedback