Activity 24 Amines Model 1 Basicity of Amines: Neutral...

Activity 24 Amines Model 1 Basicity of Amines: Neutral amines may react as either organic bases or as nucleophiles. In this model, we will focus on basicity. pKa values can be used to describe acid strength. A lower pKa indicates a stronger acid. pK$_b$ values can be used to describe base strength. Lower pK$_b$ indicates a stronger acid. Ammonia methylamine Dimethylamine aniline H H H NH$_2$ H\textasciicircum N: \textasciicircum N: \textasciicircum N: H H pK$_b$ Amine type 4.74 0° alkyl 3.36 1° alkyl 3.28 2° alkyl 9.4 aryl amine Questions: 1) Circle the most basic amine in the table above. 2) Alkyl amines become (less / more) basic as they get more substituted, because alkyl groups are generally (EWG / EDG). 3) Aniline is (less / more) basic than the alkyl amines listed above. 4) Draw one resonance structure of aniline and use the resonance structure to explain aniline's relative basicity compared to the alkyl amines.

Transcript

00:01 Hello everyone so according to the question we are going to write the reaction the reaction are given below are given below like in this way we can write the structure of reaction it will be showing okay double bone is going to be come up over here this is a paradigm along with acetic acid c h3 c o o h along with the water it's going to give you and h is going to become up over here and here it's going to become a positive sign okay and write it over here this one it's going to give you double bond as it is along with ch3 c o minus so basically what we are required to find out over here the 3d part okay four part in this particular first question pirated in and along with our d map where we can say that dmap as a 4 -dy -ethyl amino pyridine.

01:07 As we can see in this particular reactions, it's given already.

01:12 The pyridine structures and dmap, which is a stronger bronzed acid base than the pyridine.

01:19 So first of all, in the first case, we need to find out, draw the reactions.

01:24 We need to draw the reactions of each individual.

01:27 And next part, we need to estimate the k of equation.

01:30 And next we need to provide the hypothesis on the basis of our solution part so let us complete that much part then we will move further yeah so after that what we are going to be writing over here we will write the solution part like in this we will complete with this first of all it will having the shifting of the bond will be happened it will be shifted over here and this will become as in down and and this is going to become this one is going to come up over here we can see o o h c h 3 here it's going to become c okay i'll just write it in a good way so it will come h o o c and this bond is going to be attached with over here so we are getting finally we are getting the solution of this particular yeah a part will be the structure the last will be like this way double bond and it is having the positive sign along with that c h3 c o minus so when we are talking about the second that is discussed with the second part the second part will be here it will be form now pk a it's going to give you dm p mp it's a nine we can write pk a b okay it's coming b over here now not a for a also we have to write and for b also we have to write p kb is going to give you d m ap that is a 14 minus 9 we are getting 5 over here and kb is equal to dmap we are getting 10 to minus 5 that is what we are getting key of equilibrium at dm a p that will become tenders to minus 5 similarly we have to write for pkb of pyridine okay that is for pyridine we are going to be writing a year that will become a 14 minus 5 that is 9 that will remain 9 and that what we are getting for the kb of pyridine so it will be forming again 10 to minus 5 okay it will be a 9 10 is to minus 9 and the key of equations we are getting equilibrium and a pyridine we are getting 10 raised to minus 9 so this is all about the second part when we are talking about the c part so c part in her we need to find the just we need to give the specify over here so dmap is a strong base than the pyridine we are not knowing that for our r resonating effect of the formal that plus r is going to effect induce a basicity of a dmap whereas similar effect is going to be absent in the case one of a paradigm so we are going to be drawing that such kind of a structure it will be looked like this way okay so here double bond is going to become double bond double bond and this will be and going to be this bond is going to be shifted this is going to be shifted over here and this point is going to be shifted over here so what we are getting this will be the a part okay this will be the how the a will look like and in the next structure when we are talking about it will having a something like this kind of a structure okay it will have this and one more bond over here and you're getting a minus and along with two like tron here will be having it same as it is so it will mean same only this is a second b part when we are talking about talking about the c part, it will be a more good way...

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