If 380 mL of 0.35 M Ba(OH)2 are added to 500. mL of 0.65 M HCl, will the mixture be acidic or basic? Find the pH of the resulting solution.
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moles of Ba(OH)_2 = 0.35 M * 0.380 L = 0.133 moles moles of HCl = 0.65 M * 0.500 L = 0.325 moles Now, we need to find the limiting reactant. Since Ba(OH)_2 reacts with HCl in a 1:2 ratio, we need to divide the moles of HCl by 2. moles of HCl / 2 = 0.325 moles / Show more…
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