00:01
Hello everyone, let's start the question.
00:03
In this question we are given with a thioester species which has a quite long structure and it can be drawn as like this we have the carbonyl group to which sulfur is attached then we have c .h2, single bond ch2, single bond nitrogen to which hydrogen is attached and then we have the carbonyl carbon carbon carbon, ch2, ch2, h2nh carbonil group and here we have ch linked to oh.
00:44
Then we have this species onto which we have methyl above and below onto the same carbon linked to ch2 which is having an oxygen linkage.
00:58
Like this we have p double bond o, then o negative is attached, then we have oxygen, p double bond o, single bond o negative, then we have again this is linked to oxygen which is further linked to ch2 present onto this type of molecule.
01:25
And here we have oxygen and onto the next carbon we have oh and this is further linked to nitrogen like this we have a double bond then nitrogen single bond single bond like this and again it has a pyridine ring here we have nitrogen alternate double bonds are present and we have an h2 linkage onto this molecule and again here there is a presence of p single bond o negative, single bond o negative and p linked with a double bond to oxygen.
02:11
Now to this thioester, there is addition of a base and it is followed by hydrolysis.
02:22
So this is a structure of water and there is addition of base with having lone pair of electrons.
02:30
So this base will abstract this particular hydrogen and this known pair will attach onto the electrophilic carbon and carbon and the bond of electrons will shift towards this which will further lead to the formation of this molecule.
02:50
Here we have single bond o like this we have oxygen to which hydrogen is attached and here falper and the remaining big chain above which we will.
03:03
We will write in short as coa.
03:07
Now it is getting added to acid denoted as ha.
03:12
So this has, this oxygen has a negative charge and there is addition of a base as well...