Question

A sample of size n = 92 is drawn from a normal population whose standard deviation is ? = 8.2. The sample mean x? = 46.78. Part 1 of 2 (a) Construct a 99.9% confidence interval for ?. Round the answer to at least two decimal places. A 99.9% confidence interval for the mean is [ ] < ? < [ ]. Part 2 of 2 (b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain. The confidence interval constructed in part (a) (Choose one) would / would not be valid since the sample size (Choose one) is large.

          A sample of size n = 92 is drawn from a normal population whose standard deviation is ? = 8.2. The sample mean x? = 46.78.

Part 1 of 2

(a) Construct a 99.9% confidence interval for ?. Round the answer to at least two decimal places.

A 99.9% confidence interval for the mean is [     ] < ? < [     ].

Part 2 of 2

(b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain.

The confidence interval constructed in part (a) (Choose one) would / would not be valid since the sample size (Choose one) is large.

A sample of size n = 92 is drawn from a normal population whose standard deviation is ? = 8.2. The sample mean x? = 46.78.

Part 1 of 2

(a) Construct a 99.9% confidence interval for ?. Round the answer to at least two decimal places.

A 99.9% confidence interval for the mean is [ ] < ? < [ ].

Part 2 of 2

(b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain.

The confidence interval constructed in part (a) (Choose one) would / would not be valid since the sample size (Choose one) is large.

Added by Kenneth J.

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