00:01
So mass percentage of calcium carbonate, calcium carbonate is equal to 38%.
00:16
So from the given graph, we can say the initial mass of mixture, initial mass of mixture is equal to 8 .85 grams and first calcium carbonate, calcium oxalate cac2o4, it decomposes according to this equation cac2o4 when it is heated, it is converted into the calcium carbonate which is solid and carbon monoxide in the gaseous form.
01:04
So after heating, after heating, after heating, mass becomes, mass becomes constant at 7 .65 grams.
01:27
So mass of carbon monoxide evolved will be equal to initial mass of sample minus mass of sample after heating.
01:50
So mass of calcium monoxide evolved will be equal to 8 .85 grams minus 7 .65 grams which is equal to 1 .20 grams.
02:09
So now if we look at that the moles of carbon monoxide evolved will be equal to mass of carbon monoxide evolved upon molar mass of carbon monoxide.
02:31
So moles will be equal to what? 1 .20 gram upon 28 .01 gram per mole which comes out to be 0 .0428 mole...