Question

Example Three (Self Practice) Problem: Assume that the database D is given by the table below. Follow single link technique to find clusters in D. Use Euclidean distance measure. Step 1. Plot the objects in $n$-dimensional space (where $n$ is the number of attributes). In our case we have 2 attributes -- x and y, so we plot the objects p1, p2, ... p6 in 2- dimensional space: points x y p1 0.40 0.53 p2 0.22 0.38 p3 0.35 0.32 p4 0.26 0.19 p5 0.08 0.41 p6 0.45 0.30

          Example Three (Self Practice)
Problem: Assume that the database D is given by the table
below. Follow single link technique to find clusters in D. Use
Euclidean distance measure.
Step 1. Plot the objects in $n$-dimensional space (where $n$ is the
number of attributes). In our case we
have 2 attributes -- x and y, so we plot
the objects p1, p2, ... p6 in 2-
dimensional space:
points x y
p1 0.40 0.53
p2 0.22 0.38
p3 0.35 0.32
p4 0.26 0.19
p5 0.08 0.41
p6 0.45 0.30

Example Three (Self Practice)
Problem: Assume that the database D is given by the table
below. Follow single link technique to find clusters in D. Use
Euclidean distance measure.
Step 1. Plot the objects in n-dimensional space (where n is the
number of attributes). In our case we
have 2 attributes – x and y, so we plot
the objects p1, p2, ... p6 in 2-
dimensional space:
points x y
p1 0.40 0.53
p2 0.22 0.38
p3 0.35 0.32
p4 0.26 0.19
p5 0.08 0.41
p6 0.45 0.30

Added by Andrew E.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Danielle Ashley

Step 1

The objects p1, p2, p3, p4, p5, and p6 have the following coordinates: - p1: (0.08, 0.53) - p2: (0.19, 0.41) - p3: (0.32, 0.30) - p4: (0.38, 0.32) - p5: (0.6, 0.08) - p6: (0.45, 0.5) Show more…

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Agglomerative Algorithm Example Three (Self Practice) Problem: Assume that the database D is given by the table below. Follow single link technique to find clusters in D. Use Euclidean distance measure. Step 1. Plot the objects in n-points x-dimensional space (where n is the number of attributes). In our case, we have 2 attributes - x and y, so we plot the objects p1, p2, ... p6 in 2-dimensional space: .- 0.6 p5 0.08 0.5 5 p6 0.45 0.4 2 0.3 y 0.53 0.38 0.32 0.19 0.41 0.30 0.2 0.1 0 0.1 0.2 0.3 0.4 0.5 0.6x