Question

$$AgNO_3 + NaCl \rightarrow AgCl + NaNO_3$$ 25.0 mL of 0.20 M $$AgNO_3$$ is added to 50.0 mL of 0.15 M NaCl. The resulting temperature change is an increase of 1.78 °C. $$c_{sol} = 4.20 J/g °C$$ $$d_{sol} = 1.04 g/mL$$ What is the mass of the solution? $$mass_{sol} = [?] g$$ Mass of Solution Submit

Name: agno3 nacl rightarrow agcl nano3 250 ml of 020 m agno3 is added to 500 ml of 015 m nacl the resulting temperature change is an increase of 178 c csol 420 jg c dsol 104 gml what is the m 45686
Uploaded: 2021-09-12T19:46:07-08:00
Duration: 1 min 57 s
Channel: Crystal Wang
Description: agno3 nacl rightarrow agcl nano3 250 ml of 020 m agno3 is added to 500 ml of 015 m nacl the resulting temperature change is an increase of 178 c csol 420 jg c dsol 104 gml what is the m 45686

          $$AgNO_3 + NaCl \rightarrow AgCl + NaNO_3$$
25.0 mL of 0.20 M $$AgNO_3$$ is added to
50.0 mL of 0.15 M NaCl. The resulting
temperature change is an increase of
1.78 °C.
$$c_{sol} = 4.20 J/g °C$$ $$d_{sol} = 1.04 g/mL$$
What is the mass of the solution?
$$mass_{sol} = [?] g$$
Mass of Solution
Submit

agno3 nacl rightarrow agcl nano3 250 ml of 020 m agno3 is added to 500 ml of 015 m nacl the resulting temperature change is an increase of 178 c csol 420 jg c dsol 104 gml what is the m 45686

Added by Shannon T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Crystal Wang

09/12/2021

Step 1

The volume of $$AgNO_3$$ solution is $$V_{AgNO_3} = 25.0 mL$$. The volume of NaCl solution is $$V_{NaCl} = 50.0 mL$$. The total volume of the solution is the sum of the individual volumes: $$V_{total} = V_{AgNO_3} + V_{NaCl}$$ $$V_{total} = 25.0 mL + 50.0 mL = Show more…

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$$AgNO_3 + NaCl \rightarrow AgCl + NaNO_3$$ 25.0 mL of 0.20 M $$AgNO_3$$ is added to 50.0 mL of 0.15 M NaCl. The resulting temperature change is an increase of 1.78 °C. $$c_{sol} = 4.20 J/g °C$$ $$d_{sol} = 1.04 g/mL$$ What is the mass of the solution? $$mass_{sol} = [?] g$$ Mass of Solution Submit