00:01
Hi students, in this question we are given pressure p as 180m, initial temperature tis 250 kelvin, u equal to 30 meters per second, d equal to 2 .5 centimeter which is 2 .5 divided by 100 meter, then length l equal to 1 meter and t .s.
00:31
Equal to 350.
00:33
Kelvin.
00:34
We are asked to find the heat coefficient in the first part of the question and the rate of heat transfer for per one meter of cylinder length in the second part of the question.
00:44
Before that, let's first find the mean film temperature and the reynolds number.
00:50
So the mean film temperature, tf equal to g .i plus gs divided by 2 which is equal to 250 plus 350 plus 350 divided by 2 on solving 300 kelvin is obtained as mean film temperature.
01:08
From the air properties at the mean film temperature and from the dry air property start, row can be calculated as 1 .177 kilograms per meter cube v equal to 1 .568 into 10 rise to minus 5 meters square per second.
01:32
K equal to 2 .624 into 10.
01:36
10 rise to minus 2 watt per meter kelvin and pr equal to 0 .707.
01:46
From this, reynolds number of the flow can be calculated as re equal to ud by v, which is equal to 30 into 2 .5 divided by 100, all divided by 1 .568 into 10 rise to minus 5...