Air at 100 kPa and 280 K is compressed steadily to 600 kPa and 400 K. The mass flow rate of air is 0.02 kg/s and a heat loss of 16 kJ/kg occurs during the process. The power input to the compressor will be C5 kW.
Added by Shari W.
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This can be done using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. In this case, the change in internal energy can be calculated using the Show more…
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Air at 100 kPa and 280 K is compressed steadily to 600 kPa and 400 K. The mass flow rate of the air is 0.02 kg/s, and a heat loss of 16 kJ/kg occurs during the process. Assuming the changes in kinetic and potential energies are negligible, determine the necessary power input to the compressor.
Lainey R.
air is being compressed from 100 kpa and 255 k ( where it has an enthalpy of 489kj/kg) to 1000kPa and 278 K (Where it has an enthalpy of 509kJ/Kg). the exit velocity of the air from compressor is 60m/s. what is the power required in (kW) for the compressor if the load is 100kh/hr of air? ( Basis 100 kg of air =1hr)
Ali A.
Carbon dioxide enters a compressor at $100 \mathrm{kPa}$ and $300 \mathrm{K}$ at a rate of $0.2 \mathrm{kg} / \mathrm{s}$ and exits at $600 \mathrm{kPa}$ and $450 \mathrm{K}$ Determine the power input to the compressor if the process involved no irreversibilities. Assume the surroundings to be at $25^{\circ} \mathrm{C}$.
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