00:01
Determine the power delivered by this plant, assuming constant -specific heats at room temperature.
00:07
Assuming constant -specific heats, t2s is equal to t1 times pressure 1, pressure 2 over pressure 1, to the power of k minus 1 divided by k.
00:20
So we plug in our 290 times 8 to the power of 0 .4 divided by 1 .4 to get 525 .3 kelvin, t4s is then equal to our 1 ,100 kelvin times 1 8 to the power of .4 divided by 1 .4, which is 607 .2 kelvin.
00:44
Our efficiency is then equal to 1 minus t4 minus t1 divided by t3 minus t2.
00:54
So we plug in 1 minus 607 .2 minus 290 divided by 1100.
01:02
Minus 525 .3 to get .48.
01:08
Our net work, our net power, is equal to our thermal efficiency times q .n.
01:15
Our 0 .448 times 35 ,000 kilowatts.
01:24
So we get 15 ,680 kilowatts for part a.
01:30
Now for part b, assuming variable -specific heats, at temperature warmth, which is 290 kelvin, we get h1 is equal to 290 .16 kilojoules per kilogram.
01:44
P at r1 is 1 .211...