00:01
Hi, in this question we have air entering at pressure p1 equals to 26 kilo -pascal, temperature t1 equals to 230 kelvin and the velocity v1 is given as 815 meter per second.
00:19
So, we know the value of r which is gas constant is equals to 0 .287 kilojoule per k.
00:30
Kelvin the value of k is equals to 1 .4 and the value of cp equals to 1 .005 kilojoule per kg kelvin.
00:46
So now in the first part they are asking us to calculate stagnation pressure and map number upstream of the shock.
00:53
So first of all we'll calculate the stagnation temperature which is given as t01 equals equals to t1 plus v1 square divided by twice of cp.
01:10
So here we have all the values.
01:12
So we'll just put the values to get the value of t01.
01:17
So t01 will be equals to 230 plus 815 holes square divided by 2 into 1 .005.
01:31
So it was in kilojoule.
01:32
So we'll just multiply it by thousand.
01:36
So we get the value of stagnation temperature t0i equals to 560 .5 kelvin.
01:45
So now we have to calculate stagnation pressure.
01:49
So stagnation pressure p01 is given as p1 multiplied by t01 by t1 whole power k divided by k minus.
02:03
1.
02:05
So, if we put the values, we get the value of p01 equals to 26 kilo pascal multiplied by 560 .5 divided by 230 power 1 .4 divided by 1 .4 minus 1 .1.
02:26
So now after solving this, we get the value for the stagnation pressure upstream of the shock equals to 587 .3 possible.
02:41
So now we have to calculate mac number for which we'll calculate the value of velocity...