00:01
Pressure law to solve this problem let's say we have the nozzle right and right and that remember that the gas was a throttle the trucking process took place so if we say at that point of problem we have the temperature at that point let's call it the okay, t1t means truckling.
01:01
The t1t, t stands for troubling.
01:06
And that the project there also is t1t.
01:19
Entropy is b -h1t, t standing for trodling.
01:27
And we call, right? i will know that you are giving that the velocity here is dot 1 equal to 100 meter per second.
01:54
Okay, so we have v1 there.
02:06
Then let's call that the velocity at the entrance to the nozzle to be that.
02:14
All right.
02:15
Let the temperature there be t1, let the enter here, the h1, let the rutting, let the pressure b1 same thing here t2 temperature v2 velocity h1 h2 the pressure b2 the pressure we're given all these details all right so if we can just assume it's a troubling process is taking place you know that we can take this 1 t to be equal to this one here all right so h1 t constant entrapid process trucking to h1 all right so apply these so if we assume that as a steady state process and that the negligible hit and work no work and remove it we are going to arrive at equation the energy equation of the h2 minus h1 plus b2 squared has a velocity now we want to velocity at in b2 is velocity at outlet b1 is velocity at inlet okay something like this to be equal to zero right so we'll have that so if we apply the pressure law, so consider p1t, 1t, whether the pressure law, the fish mass of gas, the pressure is directly proportional to the temperature, okay? all right so we have that is equal to p okay two t over t b2 t so we are going to have that t 2 t and p to t at the end of the trotling process okay that's where this one is at the beginning so at the end of the the trolling process you have in t 2 t okay the p2 t okay okay to right at end the troubling process all right so have that so if we make t2 the formula p2t you know how is equal to p2 t times t 1 t over p1 t okay so we have we have we're doing 5 .5 bar as the outlet temperature, that's the inlet temperature to the, to the, to the nozzle.
06:35
So if that is the nozzle and we are seeing here now that it's coinciding with the, with the, it's concerned the outlet pressure of the, the inlet pressure of the nozzle is coinciding with the the other pressure of the end of the trolling process okay so we are saying that p2 t is equal to p okay p1 here p1 is at the inlet of the okay all right so for plug in to apply this and plug in everything i'm going to have this to be four to five point five okay that's ten to the power of this, so we're converting into pasta.
07:43
Then also the temperature at the initial temperature, after the beginning of the trucking process is 260 degree, which is t1t, all right? so two of this one now.
08:01
And our p1t is a 6 .9 bar at the beginning, okay? of that trucking process as well, okay? which is 6 .9, but i converted to pasca.
08:20
So if you solve this out, we're going to arrive at t2, 207, okay? 207 .25 degrees celsius.
08:37
So that's what we're going to have here.
08:39
You can apply the same law, pressure law, to consider the, what you call it now, the nozzle now so we are going to also have for the two okay the applet of the nozzle you want to look at the temperature p2 that's p2 the ablet pressure at the nozzle and the inlet pressure to the nozzle okay over the inlet pressure to the nozzle so if you're also plugging things there remember the appellate 1 .1 part given one about it to faster times t1 one if we just got now 200 now remember that t2 t2 t 2 t is equal to a t 1 all right let's go back to that one okay t2 t 1 that we have here okay these two temperature they are equal right so we'll say this two they are equal okay it's equal to that one so you can just come in the amplitude sitting here 6007 .25 all right over our p1 is 5 .5 okay 5 .5 that's our p1 on here see this this pressure is 5 .5 okay but we could come back to the same thing as the same pro is the same value as p2 t2 is two yeah equal this to the b2 2 t and p1 they are equal okay all right so if we so let me just remove these i'm just trying to let us know that these two are equal also let me just these two are equal okay all right so we just plug it in 5 .5 times 10 military power of you have this to be equal to 41 .25 degrees celsius.
11:23
Now we can just convert this to kelvin just at 273...