Aldol Reaction and Green Chemistry Questions 1. In the first...

Aldol Reaction and Green Chemistry Questions 1. In the first step two solids melt together at room temperature. Explain this phenomena. You may want to refer back to the first experiment from Organic 1 Lab (2210L) 2. Typically the reaction shows a significant change in color. Both the starting materials are aromatic, relatively colorless solids. Can you propose a reason for the observed color change? There are two possible outcomes for the Aldol reaction (Figure 17.2), which did you obtain and how do you know? 3. There are a number of base-catalyzed condensation reactions that are related to the Aldol condensation. Write an example for each of the following ""name"" reactions: a. The Claisen condensation b. The Dieckmann Condensation c. The Malonic Ester Synthesis 4. Write the reaction of 3,4-dimethoxybenzaldehyde with acetophenone using sodium hydroxide.

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00:01 Hello student we have an question that is asked in the four steps or four part so here you write what the first question which is in the first step to solid melt together at room temperature here we explain the phenomena so in the first step you write what in the first step but when n -a -o -h is react with ketone here write n -a -o -h react with what ketone then it form the an all you write it form you're right it form you write what it form you write what it form what it form what an null and here you write start reacting with aldehyde and what start reacting with with what i'll deide then here while this cause of the reaction solid melts and as the as on what completion of the reaction new solid is here formed so we come from the number two question here we can see the product so as we can see the product there is an extent conjugation is present know the conjugation here increases the lambda max here right the lambda max which is shift you write which shifts toward right what which is shift what towards you write which shift towards what longer the shift to a longer the wave length here write the wave length then this is called what bathochromic shift thus there is a significant charge in the color so the product is formed here write the product which is here you write one ring so you draw what one ring so you're drawing the ring so here you what draw the ring so it is the what so you're drawing the ring of the product so you're drawing it but ring so it is the ring so it contain what double bond it is the ring it contains double bond so in this ring is connected to another ring so here you draw the another ring is in here so it is the another rim it is connected with double bond oxygen then here it is what it is also connected with double bond oxygen so it is also connected to another ring so here you draw the structure of a ring so it is also connected a double bond here double bond is present so so it is also connected so he is connected to what ch3 co then here you write ch3 co here the melting point you write the melting point which is here you write 1780 to 181 degrees centigrade so here you draw the another product structure these are the what structure here it continuity double bond oxygen here in this position what double bonds are present so you draw here double bonds are present so this is the compound which is connected to ocs3 then above are what are two stereo isomers are possible and we come from with the melting point of the product which is obtained so you are the melting point which is 178 to 181 degree centigrade so we come from the number three in the number a bit we write the classian condensation reaction so ethyl acid to ethyline ethyline acetoacetate so you write what class write clacian condensation so you write clascion condensation so you write what classian condensation so which is what ethylene aceto acetyl the clacin condensation is between ester which containing alpha hydrogen the base is such as n a o et and et give beta ketit to esters so here you write the reaction so here it contains double bond oxygen so here oxygen is present so in this reaction the the reagent which is used which is n a o e t and another reagent which is you is s3o plus so the product is here write double…

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