00:01
So let's go over this question.
00:07
So it says that his income is $100, price of nuts is $5, and the price of apples is $10.
00:33
So at optimality, the marginal rate of substitution is equal to the price of nuts over price of that is equal to marginal utility of nuts over marginal utility of apples, which is already given to us.
01:10
So then let's plug in the prices.
01:12
So we have 5 over 10, giving us 1 half, and this is equal to a over n.
01:36
So we can get a in terms of n.
01:38
So we have 1 over 2 is equal to a over n from this.
01:45
We got all this from the marginal rate of substitution.
01:49
Cross multiply, 2a is equal to n.
02:05
Then let's write out his budget line.
02:10
Income is equal to price of a times a plus price of n times n.
02:18
His income is $100.
02:21
The price of a is 10.
02:25
The price of n is 5.
02:34
So now we can substitute.
02:37
So n is equal to 2a.
02:42
So substitute in 2a for n.
03:01
So a is equal to 5.
03:05
So basically we satisfied both the optimal or optimality, giving us optimal satisfaction using marginal rate of substitution.
03:21
And we also are trying to satisfy our budget constraint.
03:27
So we need to make sure it fits in the budget.
03:29
So it satisfies both equations.
03:32
So now we can find n.
03:34
So n is equal to 2a, and that's 2 times 5, and that's 10.
03:41
So a is equal to 5, n is equal to 10.
03:49
That's going to be our optimal bundle.
03:55
So then find two additional points on his demand curve for nuts.
04:11
So we are given price of nuts is equal to 2.
04:22
So now we go back to marginal rate of substitution, and from that we said that a over n is equal to p over n over pa.
04:36
So basically amount of apples over amount of nuts is equal to price of nuts over the price of apples.
04:42
So basically it is flipped over for the price in terms of the fraction.
04:53
So now let's substitute in the prices.
04:56
So we have that the price of apples is still 10, and then we're doing the price of nuts is 2, so we'll put that in.
05:09
So a over n is 1 over 5...