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Hello everyone.
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We are going to solve a question and from the question we have that p is equals to 0 .7, 1 minus p is equal to 0 .3 and x can take values that are 2 or 3.
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So in this a part we have to write the probability probability distribution distribution of x.
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So, here we have probability that x is equal to 2 is given by p square plus 1 minus p square, which is equals to 0 .7 square plus 0 .3 square.
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On solving this is equal to 0 .58.
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Now we are going to find the value of probability x is equal to 3, which is equal to 2 multiplied with p multiplied with 1 minus p.
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So this is equals to 2 multiplied with 0 .7 multiplied with 0 .3.
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So this is equals to 0 .48.
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Now we draw the table for the probability distribution.
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Here we have x that values is 2 and 3.
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And here we have p of x equals to x and the values are 0 .58 and for 3 this is 0 .4 .2...