00:01
Hello students, we have some questions on organic chemistry where we have to make the major products.
00:05
So halogens on reaction with alkene will give dihalo products and this will be a syn addition.
00:15
So both chlorines will be added in the same plane and the other group will be shifted in below plane.
00:23
So this will be the major product.
00:25
Similarly in the next reactant two chlorines will be added in the same plane.
00:33
These will be the major products.
00:35
Now let's look at the next questions.
00:39
In this reaction we are adding chlorine in aqueous medium.
00:43
So here first a three membered ring will be formed and the ring will be formed like this.
00:51
Here we will get a ring of chlorine in which this chlorine will have a positive charge and chloride ion will be removed.
01:04
Now since water molecules are present here so they will attack as a nucleophile in the next step and leave this bond like this.
01:18
Now in the product we will get this chlorine atom below and this water molecule will attack from above the plane in which oxygen will have a positive charge.
01:33
Now in the next step the chloride ion that was removed will abstract a proton and will make a alcohol.
01:41
So the major product will be formed like this.
01:48
It will have chlorine below the plane and a hydroxyl group above the plane and hcl will be removed.
01:56
Now let's move to the next question.
01:59
In this question as well first a three membered ring will be formed on this bond and then the ch3ch2oh this ethanol will attack on less hindered carbon.
02:12
So we will get och2ch3 here and a bromine atom here and here as well hbr will be removed.
02:22
Now both these will be added in the opposite planes.
02:26
So we can show the stereochemistry like this.
02:31
So this will be the major product.
02:33
Now let's move to the next question.
02:35
In next question we are treating this alkene with borane.
02:41
So borane will give a syn addition like this in which boron will be attached to the less hindered side.
02:53
So we will get a product that will contain a bh2 here and a hydrogen here.
02:59
Now this will be a syn addition type of reaction.
03:04
So suppose we get a bh2 group here.
03:06
Now upon reaction with alkaline solution of hydrogen peroxide this bh2 will be replaced by a hydroxyl group in the same plane.
03:19
So this will be the major product that will be formed in this reaction.
03:25
So this will be our major product.
03:30
Now let's move to the next question.
03:33
In this question we are using a deuterated borane.
03:38
So this will be added in the similar way as before...