Assume you allow 28.0 g of titanium(IV) chloride (molar mass = 189.7 g/mol) to react with 6.00 g of water. What is theoretical yield of titanium(IV) oxide? TiCl4(l) + 2 H2O(g) -> TiO2(s) + 4 HCl(g) (a) 5.90 g (b) 6.00 g (c) 11.8 g (d) 13.3 g
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Given: 6.00 g of water Molar mass of water (H2O) = 18.0 g/mol \(6.00 \, \text{g H}_2\text{O} \times \left(\frac{1 \, \text{mol H}_2\text{O}}{18.0 \, \text{g H}_2\text{O}}\right) = 0.333 \, \text{mol H}_2\text{O}\) Show more…
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