00:01
So in this problem we have a voltage applied to the plates of a parallel plate capacitor, and we're given that they carry a surface charge density.
00:08
And we want to know the distance of separation between the two plates and the electric field between the plates.
00:14
So we know that the capacitance of the parallel plate capacitor is equal to this.
00:25
And then c is the capacitance, a is the overlap between the two plates, e not is the electric constant, and d is the spacing between the plates.
00:35
And then alternatively, we can see the capacitance is q over u, where q is the charge of one plate and u is the potential difference between the plates.
00:48
And the charge can be expressed in terms of the surface charge density, sigma, times the area.
00:55
So considering all the formulas that we have above, we can see that epsilon not a over d is equal to sigma a over u, that d is equal to what epsilon not u over sigma.
01:13
And now we have all of these things.
01:15
So you can go ahead and plug this in...
