*Although we haven't covered this material in lecture yet,...

*Although we haven't covered this material in lecture yet, this exercise is an important introduction in nucleophilic acyl substitution. A good effort here will be helpful to you as we proceed through unit 3. Spend the time and look it up. \(H-O-CH_2-CH_2-O-H + H-O-C-CH_2-C-O-H \rightarrow H-O-CH_2-CH_2-O-CH_2-C-O-H + H_2O\)

Transcript

00:01 So we have given ch3 c double bond o o ch2 ch3 then we have given h oh o so we have given that this is water this is ethyl acetate okay so now we have this reversible reaction let me make you understand with the help of mechanism okay so we have this ch3 c double bond o o c h 2 c h 3 so this h oh h 2 here this o h here this is partially negative which are this h is partially positive because we have this oxygen which is electrone negative and being electronegative it withdraws the bone of electron density towards itself okay so now here we have this carbonyl carbon and this carbon is partially positive with partially positively because it is a test to electron negative oxygen atom okay so now what will happen that that this here this electron rich oh h group will approach this carbonyl carbonal carbon and the bond pair of electron will convert to loan pair of electron so this will be like ch3 c single bond o o h o c h o c h o c h 2 c h 2 c h 3 negative charge okay earlier we had two loan pair of electron now we have three loan pair of electron okay so now what will happen that this of course when it approaches so the bond will be broken right between hydrogen and oxygen and this h positive ion will be relieved right so now this h positive ion this is being approached by this electron rich oxygen atom okay and let me correct myself again so here actually what will happen that this lone pair of electron actually this this will form bond pair of electron again and the bond between this carbon and oxygen will be broken.

03:25 Okay, so let me remove this.

03:30 So now we will have a product like this, ch3, c double bond, let me draw it again.

03:46 So we have ch3, c double bond, o, oh, okay, and and now you know carbon is tetravalent in nature, right? so that's why for this region, oh group is attached here...

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