aluminum chloride has a lattice energy of -5137 kJ/mol and a heat of hydration of -5754 kJ/mol. calculate the heat of solution for ammonium chloride
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It is the sum of the lattice energy (the energy required to separate the ions in a crystal lattice) and the heat of hydration (the energy change when gaseous ions are surrounded by water molecules). However, the problem does not provide enough information to Show more…
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Write the chemical formula for aluminum chloride: Answer: Use the following data to calculate the lattice energy of aluminum chloride (s). The enthalpy of the dissociation of Cl2 (g) is 244 kJ/mol. The electron affinity of Cl (g) is -349 kJ. The enthalpy of sublimation of aluminum is +130 kJ/mol: Al(s) → Al(g) The first ionization energy of Al (g) → Al+(g) IE1 = + 578 kJ/mol The second ionization energy of Al+ (g) → Al2+(g) IE2 = + 1820 kJ/mol The third ionization energy of Al2+ (g) → Al3+(g) IE3 = + 2750 kJ/mo The enthalpy of formation of aluminum chloride is – 704.2 kJ/mol.
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Given that the heat of solution of AlBr3 is -366.5 kJ/mol and the lattice energy is -5351.7 kJ/mol, what is the heat of hydration of AlBr3?
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Use Hess's law to calculate the heat (kJ) of reaction, qrxn (kJ), when 12 g of solid calcium chloride, CaCl2, is dissolved in water. The standard state heat of formation (ΔH°f) of solid calcium chloride is -795 kJ/mol. Look up and use the standard state heats of formation of calcium and chloride ions.
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