00:01
So to solve for this, for the first question, we are to calculate the mass of aluminum produced.
00:08
If we have 1 -950 kilograms of al -203, this is alumina.
00:17
And we also have here the balance equation, right? so i won't be writing the balance equation anymore.
00:23
Let's convert this first to grams.
00:25
One kilogram is 1 ,000 grams.
00:28
And then molar mass of alumina al203 is 101 .96 grams per mole.
00:37
And as per our balance equation, two moles of al203 will produce how many moles of aluminum? four.
00:46
We're right here, four moles of aluminum.
00:48
Since we're solving for the mass of aluminum, we just need to multiply this further by the atomic mass of aluminum.
00:53
So from the predictable, we have 26 .98.
00:56
This is grams per mole.
00:58
So just cancel some units here, kilograms, grams, most of al2 .03, most of aluminum, and their remaining unit will be grams of aluminum.
01:08
So we'll have 1 .3192 .9 grams...