Aluminum reacts with oxygen according to the following reaction: 4Al(s) + 3O2(g) → 2Al2O3(s) If 24 moles of aluminum are combined with 12 moles of oxygen, how many moles of Al2O3 should form?
Added by Jack H.
Step 1
To do this, we can compare the mole ratios of the reactants to the balanced equation. For aluminum: $\frac{24 \text{ moles Al}}{4 \text{ moles Al}} = 6$ Show more…
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