Aluminum reacts with oxygen to produce aluminum oxide. 4Al(s) + 3O2(g) → 2Al2O3(s) Calculate the mass of Al2O3 that can be produced if the reaction of 55.0 g of aluminum and excess oxygen has a 68.0% yield.
Added by Alexander T.
Step 1
The molar mass of Al is approximately 26.98 g/mol. 55.0 g Al * (1 mol Al / 26.98 g Al) = 2.04 mol Al Show more…
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