Question

Aluminum reacts with oxygen to produce aluminum oxide based on the BALANCED equation: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) If 7.6 moles of Al react with excess O2, how many moles of Al2O3 can be formed?

Name: aluminum reacts with oxygen to produce aluminum oxide based on the balanced equation 4 als 3 o2g 2 al2o3s if 76 moles of al react with excess o2 how many moles of al2o3 can be formed 76967
Uploaded: 2022-02-03T17:36:25-08:00
Duration: 1 min 10 s
Channel: Ishu S
Description: aluminum reacts with oxygen to produce aluminum oxide based on the balanced equation 4 als 3 o2g 2 al2o3s if 76 moles of al react with excess o2 how many moles of al2o3 can be formed 76967

          Aluminum reacts with oxygen to produce aluminum oxide based on
the BALANCED equation:
4 Al(s) + 3 O2(g) → 2
Al2O3(s)
If 7.6 moles of Al react
with excess O2, how
many moles of
Al2O3 can be formed?

Added by Beth G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ishu S

02/03/2022

Step 1

From the balanced equation, we can see that 4 moles of aluminum react to form 2 moles of aluminum oxide. This means that the mole ratio between aluminum and aluminum oxide is 4:2, or simplified, 2:1. Show more…

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Aluminum reacts with oxygen to produce aluminum oxide based on the BALANCED equation: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) If 7.6 moles of Al react with excess O2, how many moles of Al2O3 can be formed?