Question

Aluminum sulphide reacts with oxygen according to the reaction: 2Al$_2$S$_3$(s) + 9O$_2$(g) ? 2Al$_2$O$_3$(s) + 6SO$_2$(g) A reaction mixture initially contains 5.6 mol Al$_2$S$_3$ and 25.0 mol O$_2$. Part A Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant is left? Express your answer in moles to one decimal place.

          Aluminum sulphide reacts with oxygen according to the reaction:
2Al$_2$S$_3$(s) + 9O$_2$(g) ? 2Al$_2$O$_3$(s) + 6SO$_2$(g)
A reaction mixture initially contains 5.6 mol Al$_2$S$_3$ and 25.0 mol O$_2$.
Part A
Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant is left?
Express your answer in moles to one decimal place.

Aluminum sulphide reacts with oxygen according to the reaction:
2Al2S3(s) + 9O2(g) ? 2Al2O3(s) + 6SO2(g)
A reaction mixture initially contains 5.6 mol Al2S3 and 25.0 mol O2.
Part A
Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant is left?
Express your answer in moles to one decimal place.

Added by Ruben P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Bridger Johnston

Step 1

The balanced chemical equation for the reaction between aluminum sulfide and oxygen is given as: 2Al2S3 (s) + 9O2 (g) → 2Al2O3(s) + 6SO2(g) Show more…

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Aluminum sulphide reacts with oxygen according to the reaction: 2Al2S3 (s) + 9O2 (g) → 2Al2O3(s) + 6SO2(g) A reaction mixture initially contains 5.6 mol Al2S3 and 25.0 mol O2. Part A: Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant is left? Express your answer in moles to one decimal place.