Ammonia rapidly reacts with hydrogen chloride, making ammonium chloride. Calculate the number of grams of excess reactant when 4.21g of NH3 reacts with 4.76g of HCl.
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Given: Mass of NH3 = 4.21 g Molar mass of NH3 = 17 g/mol Number of moles of NH3 = Mass of NH3 / Molar mass of NH3 Number of moles of NH3 = 4.21 g / 17 g/mol Number of moles of NH3 ≈ 0.25 mol Show more…
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Ammonia rapidly reacts with hydrogen chloride, making ammonium chloride. Write a balanced chemical equation for the reaction, and calculate the number of grams of excess reactant when $3.0 \mathrm{g}$ of $\mathrm{NH}_{3}$ reacts with $5.0 \mathrm{g}$ of $\mathrm{HCl}$.
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