00:01
Hello students, so here we have given that a number of mole of nh3 is equal to 5 mole, okay? then the number of mole of o2 is given here 12 .6 mole, okay? then number of mole of oxygen left, that is equal to 5 .5 mole.
00:28
So, the number of mole of oxygen consumed is given here 12 .6 minus 5 .5.
00:41
So it is 7 .1 mole.
00:44
Then again, the reaction is, let us x mole of oxygen consumed in the reaction.
00:53
X mole oxygen is consumed.
00:56
Just suppose it.
00:58
So 4 molecule of n h3 reacted with 5 molecule of o2 that give formation of 4 molecule of no and then 6 h2 okay, so as you can write that as 5 mole o2 react with 4 mole nh3 so it is x mole react with that 4x upon 5 mole okay so as a mole of n s 3 consumed ns 3 mole consumed it will mole of n o will be formed that is equal to the mole of n o will be formed then again as the so you can write that mole of n o formed is equal to 4x upon 5 you can write it simply in this form then we have given the other reaction that 4 molecule of n s 3 reacted with 7 o2 and it give formation of 4 molecule of n o2 and plus 6 molecule of h2 okay then here this amount is 7 .1 minus x then you can write that 7 mole oxygen react with 4 mole n h3 okay so you can write at 7 .1 minus x amount oxygen react with 4 by 7 and 7 .1 minus x so as mole of an o2 as mole of an o2 will equal to mole of n h3 consumed that is equal to 4 by 7 7 .7.
03:00
7 .1 minus x mole okay then the total mole of n h3 consumed total mole of n h3 consumed here is 4x upon 5 and plus 4 by 7 7 .1 minus x so you can write that 28x plus 142 minus 20x upon total it is 35 35 that is equal to 5...