Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g)ΔHrxn=−906kJ Calculate the heat (in kJ) associated with the complete reaction of 305 g of NH3. Express your answer with the appropriate units.
Added by Cheryl G.
Step 1
The molar mass of nitrogen (N) is approximately 14.01 g/mol, and the molar mass of hydrogen (H) is approximately 1.01 g/mol. So, the molar mass of NH3 = 14.01 g/mol + (3 × 1.01 g/mol) = 14.01 g/mol + 3.03 g/mol = 17.04 g/mol. Show more…
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Ammonia reacts with oxygen according to the reaction 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), ΔHrxn = -906 kJ. Calculate the heat associated with the complete reaction of 155 g of NH3. Express the answer in kilojoules to three significant figures.
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Ammonia reacts with oxygen according to the equation: 4 NH3 (g) + 5 O2 (g) → 4 NO(g) + 6 H2O(g) ΔHrxn = -906 kJ. Calculate the heat (in kJ) associated with the complete reaction of 155 g of NH3.
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Ammonia reacts with oxygen according to the equation: 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), ΔHrxn = -906 kJ Calculate the heat (in kJ) associated with the complete reaction of 155 g of NH3.
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