Question

An 7.00-kg box sits on a ramp that is inclined at 33.0∘ above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is μk = 0.300. A constant horizontal force F = 26.0 N is applied to the box (Figure 1), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? v=??m/s

Name: an 700 kg box sits on a ramp that is inclined at 330 above the horizontal the coefficient of kinetic friction between the box and the surface of the ramp is k 0300 a constant horizontal forc 62633
Uploaded: 2022-07-15T14:32:44-08:00
Duration: 2 min 31 s
Channel: Pritesh Ranjan
Description: an 700 kg box sits on a ramp that is inclined at 330 above the horizontal the coefficient of kinetic friction between the box and the surface of the ramp is k 0300 a constant horizontal forc 62633

          An 7.00-kg box sits on a ramp that is inclined at 33.0∘ above
the horizontal. The coefficient of kinetic friction between the box
and the surface of the ramp is μk = 0.300. A constant horizontal
force F = 26.0 N is applied to the box (Figure 1), and the box
moves down the ramp.
If the box is initially at rest, what is its speed 2.00 s after
the force is applied?
v=??m/s

Added by Glen M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Pritesh Ranjan

07/15/2022

Step 1

00 kg Acceleration due to gravity, g = 9.8 m/s^2 Weight, W = m * g W = 7.00 kg * 9.8 m/s^2 W = 68.6 N Show more…

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An 7.00-kg box sits on a ramp that is inclined at 33.0∘ above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is μk = 0.300. A constant horizontal force F = 26.0 N is applied to the box (Figure 1), and the box moves down the ramp. If the box is initially at rest, what is its speed 2.00 s after the force is applied? v=??m/s